X^2+1-35=-6x-5

Solution for X^2+1-35=-6x-5 equation:

X^2+1-35=-6X-5

We move all terms to the left:

X^2+1-35-(-6X-5)=0

We add all the numbers together, and all the variables

X^2-(-6X-5)-34=0

We get rid of parentheses

X^2+6X+5-34=0

We add all the numbers together, and all the variables

X^2+6X-29=0

a = 1; b = 6; c = -29;
Δ = b2-4ac
Δ = 62-4·1·(-29)
Δ = 152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{152}=\sqrt{4*38}=\sqrt{4}*\sqrt{38}=2\sqrt{38}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{38}}{2*1}=\frac{-6-2\sqrt{38}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{38}}{2*1}=\frac{-6+2\sqrt{38}}{2}
$